Question

(x la a doua +x+1)totul la a doua
(x+y+2)la a doua
(x la a doua-x+1)la a doua
(2x-3+x la a doua) totul la a doua

Answer 1

(x`2+x+1)(x+y+2)
(x+x+2)(x+y+2)
(2x+2)(x+y+2)


(x`2-x-1)(2x-3+x`2)
(x-x-1)(2x-3+x`2)
(-1)(2x-3+x)
(-1)(x-3)

nu stiu daca este bine

Answer 2

***
$(x ^{2} + x + 1)^{2} = x ^{4} +x^{2} + 1 + 2x ^{3} + 2x ^{2} + 2x$
$= x ^{4} + 2x^{3} + 3 x^{2 } + 2x + 1$
****
$(x + y + 2) ^{2} = {x}^{2} + {y}^{2} + 4 + 2xy + 4x + 2y \times 2$
$= {x}^{2} + {y}^{2} + 4 + 2xy + 4x + 4y$
****
$(x ^{2} - x + 1) ^{2}$
$= {x}^{4} + ( - x) ^{2} + 1 - {2x}^{3} + {2x}^{2} + 2x$- 2x
$= {x}^{4} + x^{2} +1 - 2x ^{3} -2x^{2} - 2x [tex] = x ^{4} + {3x}^{2}$