Question

X la a doua -x supra x+1 =3 supra 2

Answer 1

2(x`2-x)=3(x+1) 2x`2-2x=3x+3 2x`2-2x-3x-3=0 2x`2-5x-3=0 2x`2-6x+x-3=0 2x(x-3)+(x-3)=0 (x-3)(2x+1)=0 x-3=0 x=3 2x+1=0 2x=-1 x=-1/2

Answer 2

[tex] \frac{ x^{2}-x }{x+1} = \frac{3}{2} \\ 2 x^{2} -2x=3x+3 \\ 2 x^{2} -2x-3x-3=0 \\ 2 x^{2} -5x-3=0 \\delta= 5^{2} -4(-3)(2)=25+24=49 \\ x_{1} = \frac{5+ \sqrt{49} }{4} = \frac{5+7}{4}= \frac{12}{4} =3} \\ x_{2} =\frac{5- \sqrt{49} }{4}=\frac{5-7}{4}=\frac{-2}{4}=- \frac{1}{2} [/tex]