Question

x la patrat supra radical din 7+radical din 3 = radical dn 7 - radical din 3 = ?

Answer 1

$(1)\;...\;\frac{x^2}{\sqrt7}+\sqrt3=\frac{\sqrt7(x^2+\sqrt{7*3})}{7}=\frac{\sqrt7x^2+7\sqrt3}{7}$
$(2)\;\;...\;\sqrt7\;-\;\sqrt3\approx2,65\;-\,1,73=0,92$