Question

x la putearea 2 -5x+6=0 x1 supra x2 + x2 supra x1 va rogg? as dori tot exercitiul , nu doar raspunsull ... Multumesc

Answer 1

$x^{2} -5x+6=0$
Trebuie sa aflam solutiile $x_{1,2}$ .
[tex] x^{2} -5x+6=0 \\ x^{2} -3x-2x+6=0 \\ x(x-3)-2(x-3)=0 \\ (x-3)(x-2)=0 \\ [/tex]
deci 
$x_{1} =2 \\ x_{2} =3$
Raportul :$\frac{x_1}{x_2} + \frac{x_2}{x_1} = \frac{2}{3} + \frac{3}{2} = \frac{2*2+3*3}{6} = \frac{13}{2} =6.5$