Question

x la puterea 2-y la puterea 2 supra xy pentru x=1_radical 3 , y=1+radikal 3 aflat v alö area rapoRtului algebric

Answer 1

$\frac{ x^{2} - y^{2}}{xy} = \frac{(x-y)(x+y)}{xy} =$
$= \frac{(1- \sqrt{3}- 1- \sqrt{3})*(1- \sqrt{3}+ 1+ \sqrt{3})}{(1- \sqrt{3})* (1+ \sqrt{3})} =$
$= \frac{(- 2\sqrt{3})*2}{(1- 3)} = \frac{(- 2\sqrt{3})*2}{(1- 3)}$
$= 2\sqrt{3}$