Question

X la puterea a 2 + y la puterea a 2 = 36
X la puterea a 2-6y=36 ajutați mă va rog

Answer 1

x^2+y^2=36
x^2-6y=36
Scadem relatiile
y^2+6y=0
Folosim ecuatia de gradul 2
delta=6^2-4•1•0=36-0=36
Y1,2=-6+-6/2
y1=-6+6/2=0/2=0
y2=-6-6/2=-12/2=-6
Inlocuim in prima relatie si obtinem
x1,2^2+y1^2=36=>x1,2^2=36=>x1,2=+-6
x1=6
x2=-6
x3^2+y2^2=36=>x3^2+36=36=>x3^2=0=>x3=0
Deci solutii sunt perechile:(6,0);(-6;0);(0;-6)