Question

x la puterea a doaua +2x+1=7+4 radical din 3

Answer 1

$x^{2} +2x+1=7+4 \sqrt{3} \\ (x+1) ^{2} =4+4 \sqrt{3} +3 \\ (x+1)^{2} =(2+ \sqrt{3}) ^{2} =>|x+1|=2+ \sqrt{3} => \\ =>x=1+ \sqrt{3}~sau~x=-3- \sqrt{3}.$