Question

x patrat+5x+4
descompuneti in factori .
se face cu delta ?

Answer 1

$x^{2} +5x+4=0 \\ \Delta=25-4*4=25-16=9 \\ x_1= \frac{-5-3}{2}= \frac{-8}{2}=-4 \\ x_2 =\frac{-5+3}{2}= \frac{-2}{2}=-1 \\ a x^{2} +bx+c=a(x-x_1)(x-x_2) \\ x^{2} +5x+4=(x+4)(x+1)$