Question

x patrat+ cunci pe sasex+unupesase=o

Answer 1

$x^{2} + \frac{5x}{6} + \frac{1}{6} =0 \ \textless \ =\ \textgreater \ 6 x^{2} +5x+1=0$
Δ=5²-4·6·1
Δ=25-24
Δ=1 =>√Δ=1
x₁=(-5-1)/12=(-1/2)
x₂=(-5+1)/12=(-1/3)
=>ecuatia se descompune : (x+1/2)(x+1/3)=0