Question

(x+radical din 3)la 2-10=x la 2-(radical din 3 +2)la 2=?

Answer 1

$(x+ \sqrt{3} )^2-10=x^2-( \sqrt{3} +2)^2 \\ x^2+2*x* \sqrt{3} + \sqrt{3} ^2-10=x^2-( \sqrt{3} ^2+2* \sqrt{3} *2+2^2) \\ x^2+2x \sqrt{3} +3-10=x^2-3-4 \sqrt{3} -4 \\ x^2-x^2+2x \sqrt{3} =-3-4-3+10-4 \sqrt{3} \\ 2x \sqrt{3} =-4 \sqrt{3} \\ x=- \frac{4 \sqrt{3} }{2 \sqrt{3} } \\ x=-2$