Question

x/ radical din 6 =7 radical din 30/15 plus radical din 30 supra 5,va rog repede​

Answer 1

Răspuns:

Explicație pas cu pas:

$\dfrac{x}{\sqrt{6} } = \dfrac{7\sqrt{30} }{15} + \dfrac{^{3)} \sqrt{30} }{5}$

$\dfrac{x}{\sqrt{6} } = \dfrac{7\sqrt{30} + 3\sqrt{30}}{15}$

$\dfrac{x}{\sqrt{6} } = \dfrac{10\sqrt{30}^{(5} }{15} \iff \dfrac{x}{\sqrt{6} } = \dfrac{2\sqrt{30}}{3}$

$x = \dfrac{2\sqrt{30} \cdot \sqrt{6} }{3} = \dfrac{2 \cdot 6\sqrt{5}^{(3} }{3}$

$\implies x = 4\sqrt{5}$