Question

x radical din (radical din 3 -2)^2 + x radical (3 - 2 radical din 3)^2 + x radical din (radical din 3 - 3) ^2

Answer 1

x√(√3-2)² + x√(3-2√3)² + x√(√3-3)² =

= x(2-√3) + x(2√3-3) + x(3-√3) =

= 2x-√3x + 2√3x - 3x + 3x - √3x = 

= 2x - √3x + 2√3x - √3x = 2x + 0 = 2x