Question

X radical din2+xradical din8+x radical din32=radical din4+radical din16+radical din64
Radical din5(x+4)+2radical din5(x-2)=radical din15
CORONITA!!VA ROG!'$:#

Answer 1

x√2 + x√8 + x√32 = √4 + √16 + √64 
x√2 + 2x√2 + 4x√2 = 2 + 4 + 8
7x√2 = 14 
x√2 = 14/7
x√2 = 2 
x = 2 / √2 
x = 2√2 / 2 
x = √2


√5(x + 4) + 2√5 (x - 2) = √15
x√5 + 4√5 + 2x√5 - 4√5 = √15
3x√5 = √3×√5   
3x = √3 
x = √3/3