Question

x+$x+ \sqrt 2=0$

8 x = 0,16

$x^{2} =6$

Answer 1

[tex]x+x+\sqrt2=0\\ 2x+\sqrt2=0\\ 2x=-\sqrt2\\ x=-\dfrac{\sqrt2}{2}\\ \\ 8x=0,16\\ x=\dfrac{0,16}{8}=0,02=\dfrac{1}{50}\\ \\ x^2=6 \Rightarrow x \in \lbrace \pm \sqrt6 \rbrace[/tex]