Question

[x] +[x+1]+[x+2]+.......+[x+60]=2013

Answer 1

[x] +[x+1]+[x+2]+.......+[x+60]=2013

[x] +[x]+1+[x]+2+.......+[x]+60=2013; de la 0 la 60 sunt 61 de numere

61•[x]+(1+2+3+…+60)=2013

61•[x]+60•61/2=2013

61•([x]+30)=2013    /:61

[x]+30=33

[x]=3

=> x∈[3; 4)