Question

x+y=162,y+z=354,x+z=408 alfa valori le pentiti x y z

Answer 1

x+y=162

y+z=354, y=354-z

x+z=408, x=408-z

inlocuim pe x si y,

408-z+354-z=162

408+354-162=2z

600-162=2z

438=2z,

z = 219,

y+z=354, y+219=354, y=354-219,

y = 135

x+z=408, x+219=408, x=408-219,

x = 189