Question

x=y+3
x+y=1
metoda substitutiei

x-y=5
x+y=3
metoda reducerii

x-2y=-1
2x+3y=12
metoda reducerii


va rog mult ajutati ma​

Answer 1

il inlocuiesti pe x
y+3+y=1
2y=1-3
2y=-2
y=-1

x+y-(x-y)=3-5
x+y-x+y=-2
2y=-2
y=-1

2x+3y-2(x-2y)=12+2
2x+3y-2x+4y=14
7y=14
y=2