Question

X+y= 700, y+z=500, x+z= 800, aflati x,y,z

Answer 1

Răspuns:

Explicație pas cu pas:

x+y=700  ;      y+z=500   ;       x+z=800

x+y + y+z + x+z =700+500+800

2x+2y+2z = 2000

2(x+y+z ) =2000

x+y+z =2000:2 =1000

(x+y)+z =1000

700+z=1000  ;     z=1000-700 =300

y+300 =500  ;   y=500-300 = 200

x+300 =800 ;    x=800-300 =500