Question

(x,y.z) d.p (2,8,10)
mg (m,g) = 12
ma (x,y,z) = ?

Answer 1

(x,y.z) d.p (2,8,10); mg (x,y) = 12

x=2k; y=8k si z=10k

mg (x,y) =√(2k·8k)=√(16k²)=4k

4k=12 => k=3

x=2·3=6

y=8·3=24

z=10·3=30

ma (x,y,z)=(x+y+z)/3=(6+24+30)/3

ma (x,y,z)=60/3=20

sau, ma (x,y,z)=(2k+8k+10k)/3=20k/3=60/3=20