Question

{x,y,z}d.p.{3,7,2} si xy+yz=175

Answer 1

x/3=y/7=z/2=k

x=3k⇒3√5

y=7k⇒7√5

z=2k⇒2√5

3k*7k+7k*2k=175

21k²+14k²=175

35k²=175|:5

7k²=35|:7

k²=5

k=√5

Vf. 3√5*7√5+7√5*2√5=21*5+14*5=105+70=175