Question

{x,y,z} d.p {5,3,6} x+y+z= 47

Answer 1

$\frac{x}{5}=\frac{y}{3}=\frac{z}{6}=\frac{47}{14}\\ \\ x=\frac{5*47}{14}=235/14\\ \\ y=\frac{3*47}{14}=141/14\\ \\ x=\frac{6*47}{14}=282/14\\ \\ proba... (235+141+282):14=47$

Answer 2

x+y+z=47
x pe 5=y pe 3= z pe 6=k
x egal cu 5k
y cu 3 k
z cu 6 k
5+3+6k=47
14k=47
k=3,3571428