Question

x,y,z d.p 7 4 5
x+y+z=32​

Answer 1

( x, y, z ) d p ( 7, 4, 5) => x = 7k, y = 4k, z = 5k

x + y + z = 32

inlocuim : 7k + 4k + 5k = 32

16k = 32

k = 2 => x = 7 • k = 7 • 2 = 14

y = 4 • k = 4 • 2 = 8

z = 5 • k = 5 • 2 = 10

concluzie : x = 14, y = 8, z = 10.