Question

{x,y,z} d.p. cu {1,(4); 1,(5); 1,(6)} iar media aritmetica este 168. Sa se afle x,y si z .Mie nu mi da de nici un fel.Cum se poate rezolva.Va multumesc.

Answer 1

1,(4)=(14-1)/9=13/9
1,(5)=(15-1)/9=14/9
1,(6)=(16-1)/9=15/9
x=1k/9
y=14k/9
z=15k/9
(1k/9+14k/9+15k/9)/3=168
1k/9+14k/9+15k/9=504
k+14k+15k=4536
30k=4536
k=151,2
x=151,2/9=16,8
y=14×151,2/9=235,2
z=15×151,2/9=252

verificare (16,8+235,2+252)/3=504/3=168