Question

X,Y,Z direct proportionale cu 3,4,5 2•(X•Y+X•Z+Y•Z)=376 X=? Y=? Z=?

Answer 1

X/3=Y/4=Z/5=K =>
X=3K=3*2=6
Y=4K=4*2=8
Z=5K=5*2=10

2(3K*4K+3K*5K+4K*5K)=376
12K*K+15K*K+20K*K=376:2
47 K^2=188
K^2=188:47
K^2=4 => K=2 înlocuim mai sus( eu deja am scris acolo)