Question

{x,y,z} dp. {6,8,10}
xy+yz+zx=188​

Answer 1

Explicație pas cu pas:

$\dfrac{x}{6} = \dfrac{y}{8} = \dfrac{z}{10} = k$

$x = 6k; \ y = 8k; \ z = 10k$

$xy + yz + zx = (48 + 80 + 60) {k}^{2} = 188 {k}^{2}$

$188 {k}^{2} = 188 \iff {k}^{2} = 1 \implies k = 1$

$\implies x = 6; \ y = 8; \ z = 10$