Question

{x,y,z} i.p. {2,4,6}
X+y+z=22
Dau coroana.

Answer 1

x/2=y/4=z/6=k
x=2k,  y=4k,  z=6k
x+y+z=22⇒2k+4k+6k=22

12k=22

k=11/6
x=2k=2×11/6=11/3
x=11/3

y=4k=4×11/6=22/3
y=22/3

z=6k=6×11/6=11
z=11

x=11/3, y=22/3  si z=11
verificare
a+b+c=22
11/3+22/3+11=(11+22+33)/3=66/3=22
22=22