Question

(x,y,z,t) ip (2,3,4,5)
4y+2t=132

Answer 1

2x=3y=4z=5t=k => x=k/2; y=k/3; z=k/4 si t=k/5. ;;4*k/3+2*k/5=132=> 20k+6k=15*132 => 26k=1989 => k=1980/26 => k=990/13=> x=495/13; y=330/13; z=495/26 si t=198/13.