Question

x2+12x+8 este egal cu 0

Answer 1

${x}^{2} + 12x + 8 = 0$

$a = 1$

$b = 12$

$c = 8$

$\Delta = {b}^{2} - 4ac$

$\Delta = {12}^{2} - 4 \times 1 \times 8$

$\Delta = 144 - 32$

$\Delta = 112 > 0 = > \exists \: x_{1} \: \neq \: x_{2}\:\in\:\mathbb{R}$

$x_{1,2}=\frac{-b\pm\sqrt{\Delta}}{2a}$

$x_{1,2}=\frac{-12\pm\sqrt{112}}{2 \times 1}$

$x_{1,2}=\frac{-12\pm4\sqrt{7}}{2}$

$x_{1,2}=\frac{4(-3\pm\sqrt{7})}{2}$

$x_{1,2}=2( - 3 \pm \sqrt{7} )$

$x_{1,2}= - 6 \pm2 \sqrt{7}$

$x_{1}= - 6 + 2 \sqrt{7}$

$x_{2}= - 6 - 2 \sqrt{7}$