Question

(x²+2)(2x-3)≤0 ajutati-ma va rog la rezolve

Answer 1

Observam ca $x^{2} +2\ \textgreater \ 0.$ Tinand cont de $( x^{2} +2)(2x-3) \leq 0$, rezulta $2x-3 \leq 0=\ \textgreater \ 2x \leq 3=\ \textgreater \ x \leq \frac{3}{2} . \\ Solutie:~\boxed{x\in(-\infty; \frac{3}{2}] }.$