Question

x2+4x-12=0 cum se rezolva aceasta ecuatie??

Answer 1

pai atunci e ecuatie de grad 2
delta =b(patrat)-4ac=16+48=64
X1,=-b+radical din delta supra 2a=-4+8/2=2
x2=-b-radical din delta supra 2a=-4-8/2=-6

Answer 2

$x^{2} +4x-12=0 \\ \Delta= b^{2}-4*a*c= 16-4*(-12)*1=16+48=64 \\ x_1= \frac{-b- \sqrt{\Delta} }{2a}= \frac{-4-8}{2}= \frac{-12}{2}=-6 \\ x_2= \frac{-b+ \sqrt{\Delta} }{2a}=\frac{-4+8}{2}= \frac{4}{2}=2$
S={-6; 2}