Question

X² - 8x + 12
vă rog ​

Answer 1

$x^2 - 8x + 12$

$x^2-8x+12=0$

$x_{1,2} = \frac{{ - b \pm \sqrt {b^2 - 4ac} }}{{2a}}}$

$x_{1,2} = \frac{{ - (-8) \pm \sqrt {64- 4 \cdot 12} }}{{2}}}$

$x_{1,2} = \frac{{ - (-8) \pm \sqrt {64- 48} }}{{2}}}$

$x_{1,2} = \frac{{ - (-8) \pm \sqrt {16} }}{{2}}}$

$x_{1,2} = \frac{{ 8\pm 4 }}{{2}}}$

$x_{1} = \frac{12}{2} =6$

$x_{2} = \frac{4}{2} =2$

$x^2-8x+12=(x-2)(x-6)$

Answer 2

Răspuns:

Explicație pas cu pas:

x²-8x+12=0

x1,2=(8±√√64-48)/2=(8±√16)/2=(8±4)/2

x1=12/2=6      si x2=4/2=2

x²-8x+12=(x-2)(x-6)