Question

(x² +9)[3(x - 1) - 2(x+1)] ≤0. ​

Answer 1

Explicație pas cu pas:

$( {x}^{2} + 9) [3(x - 1) - 2(x + 1)] \leqslant 0$

$( {x}^{2} + 9) (3x - 3 - 2x - 2) \leqslant 0$

$( {x}^{2} + 9) (x - 5) \leqslant 0$

${x}^{2} + 9 > 0 \ , \ \ \forall \ x \in \mathbb{R}$

$\implies x - 5 \leqslant 0 \iff x \leqslant 5 \\ \implies x \in \Big(-\infty ;5 \Big]$