Question

X2-9x+8 < sau = ca 0???va rig frumos

Answer 1

$x^2-9x+8 \leq 0 \\ (x-1)(x-8) \leq 0 \\ x-1 \leq 0 \\ x \leq 0+1 \\ x \leq 1 \\ x-8 \leq 0 \\ x \leq 0+8 \\ x \leq 8$