Question

X²+(x-1)=1 va rog mult

Answer 1

pt x-1>=0
x-1=1-x²
x²+x-2=0
Δ=1+8
Δ=8
x₁,₂=-(1+-3)/2
x₁=2
x₂=-1
sau pt x-1<0
x-1=x²-1
x²-x=0
x(x-1)=0
x=0 sau x=1
=> S={0,1,-1,2}