Question

XI.4.142. Să se afle a din expresia:
98 – 36: [64 – (3 x a + 40) : 5 +4]= 96

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Answer 1

Răspuns: $\red{\Large\boxed{\bf a = 70}}$

Explicație pas cu pas:

$\large\bf 98-36: [64-(3\cdot a + 40) : 5 +4]= 96$

$\large\bf 98= 96 +36: [64-(3\cdot a + 40) : 5 +4]$

$\large\bf 98-96=36: [64-(3\cdot a + 40) : 5 +4]$

$\large\bf 2=36: [64-(3\cdot a + 40) : 5 +4]$

$\large\bf 2\cdot [64-(3\cdot a + 40) : 5 +4] =36~~~\bigg|:2$

$\large\bf 64-(3\cdot a + 40) : 5 +4 =18$

$\large\bf 64-(3\cdot a + 40) : 5 =18 -4$

$\large\bf 64-(3\cdot a + 40) : 5 =14$

$\large\bf 64=14+(3\cdot a + 40) : 5$

$\large\bf 64-14 =(3\cdot a + 40) : 5$

$\large\bf 50 =(3\cdot a + 40) : 5~~~\bigg|\cdot5$

$\large\bf 250 =3\cdot a + 40$

$\large\bf 250 -40 =3\cdot a$

$\large\bf 210=3\cdot a~~~\bigg|:3$

$\red{\Large\boxed{\bf a = 70}}$

#copaceibrainly

Answer 2

Răspuns:

98 – 36: [64 – (3 x a + 40) : 5 +4]= 96

36:[64-(3·a+40):5+4]=98-96

64-(3·a+40):5+4=36:2

64-(3·a+40):5=18-4

(3·a+40):5=64-14

3·a+40=50·5

3·a=250-40

a=210:3

a=70