Question

Xpatrat+5x+4=0 rezolvare completa

Answer 1

x^2+5x+4=0; (x+1)(x+4)=0; x=-1;x=-4;S={-1;-4}

Answer 2

$\displaystyle x^2+5x+4=0 \\ \\ \Delta=b^2-4ac \\\\ \Delta=5^2-4\cdot1\cdot4 \\\\ \Delta=25-16=9 \\ \\ X_{1,2}= \frac{-b\pm \sqrt{\Delta} }{2a} = \\ \\ \\ X_1=\frac{-5+3}{2}=-1 \\ \\ \\ X_2= \frac{-5-3}{2}= \frac{-8}{2}=-4$