Question

xy+x-3y+3=0 determinati perechi (x,y) de numere intregi nenule

Answer 1

xy+x−3y+3=0
xy+x−3y+3+−3=0+−3
xy+x−3y=−3
xy+x−3y+3y=−3+3y
xy+x=3y−3
x(y+1)=3y−3
$\frac{x(y+1)}{y+1}= \frac{3y-3}{y+1}$
$x= \frac{3y-3}{y+1}$