Question

xz+yz stind-ca x+y=24 z=10

Answer 1

$x+y=24 \\ z=10 \\ xz+yz=z(x+y)=10 \cdot 24=240 \\ \boxed{xz+yz=240}$

Answer 2

daca x+y=24 si z=10 atunci
xz+yz=z(x+y)=10*24=240