Question

y = (‒ 1)^2k + (‒ 1)^2k+1 (oricare ar fi k∈N)

Answer 1

   
[tex]2k = \text{numar par, oricare ar fi } k \in N\\ 2k+1 = \text{numar impar, oricare ar fi } k \in N\\\\ y = (-1)^{2k} + (-1)^{2k+1} = 1^{2k} - 1^{2k+1} = 1 - 1 = \boxed{\bf 0}[/tex]