Question

y=[(11-0 la puterea 11 ) *(3 la puterea 3 - 3 la puterea 2 )+1 la puterea 2020]*(3 la puterea 2-2 la puterea 3) -3 la puterea 2* 2

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Answer 1

Răspuns:

Explicație pas cu pas:

4^32*2^34 = 2^64*2^24 = 2^98

(2^25)^5 = 2^125

2^4*2^23 = 2^27

2^125 : 2^27 = 2^98

7^5 :7^5 - 1 = 1 -1 = 0

0^32*4 = 0*4 = 0

x = 2^99:(2^98 +2^98) = 2^99:(2*2^98) =

2^99 : 2^99 = 1

11 -0^11 = 11

3^3 -3^2 = 27 -9 = 18,  1^2020 = 1

3^2 -2^3 = 9 -8 = 1,  3^2*2 = 18

y= [11 * 18 + 1]*1 -18 = 11*18 -18 + 1 =

  10*18 + 1 = 181