Question

y = \sqrt{2} x ( \sqrt{2} + \frac{1}{ \sqrt{2} } )$\frac{1}{ \sqrt{2} }$

Answer 1

[tex]y= \sqrt{2} ( \sqrt{2} + \frac{1}{ \sqrt{2} } ) \frac{1}{ \sqrt{2} } =\ \textgreater \ \\\\ y= \sqrt{2} ( \frac{2 \sqrt{2}+ \sqrt{2} }{2} ) \frac{1}{ \sqrt{2} } =\ \textgreater \ \\\\ y= \sqrt{2} * \frac{3 \sqrt{2} }2} * \frac{ \sqrt{2} }{2} =\ \textgreater \ \\\\ y= \frac{6 \sqrt{2} }{2} \\\\ y=3 \sqrt{2} [/tex]