Question

z=(3+2i)(3-2i)-(4-i).​

Answer 1

z=9-4i²-4+i=-4i²+i+5, care e ecuație de gradul al doilea.

∆=1-4×(-4)×5=1+80=81

i¹=-1+9/-8=8/-8=-1

i²=-1-9/-8=-10/-8=5/4

S={-1;5/4)