Question

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Answer 1

$In \ prima \ figura,aria \ suprafetei \ hasurate \ este:$

$A=A_{patrat}-4A_{triunghi \ dreptunghic}$

$A=(a+b)^2-\frac{4ab}{2}$

$A=a^2+b^2+2ab-2ab$

$A=a^2+b^2$

$In \ a \ doua \ figura \ aria \ suprafetei \ hasurate \ este:$

$A'=A_{patrat}-4A_{dreptunghi}$

$A'=(a+b)^2-\frac{4a(a+b-a)}{2}$

$A'=a^2+b^2+2ab-2ab$

$A'=a^2+b^2$

$A=A'$