Question

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Answer 1

Patrulaterul este paralelogram, laturile opuse II doua cate doua, se aplica teorema lui Thales si rezulta perimetrul=17,1 dm.

Answer 2

HS║AE, L∈AE ⇒ HS║AL (1)
TA║SL, H∈TA ⇒ HA║SL (2)
Din (1)(2) ⇒ HALS - paralelogram ⇒ HA=LS, AL=SH
HS║AE ⇒ (Th. Thales) $\frac{TH}{HA} = \frac{TS}{SE}$
$\frac{3}{HA} = \frac{5}{8} =\ \textgreater \ HA = \frac{3*8}{5} = \frac{24}{5} = 4.8 dm$ ⇒ HA = LS = 4.8 dm 
TA║SL ⇒ $\frac{ES}{ST} = \frac{EL}{LA} =\ \textgreater \ \frac{8}{5} = \frac{6}{LA} =\ \textgreater \ LA = \frac{6*5}{8} = \frac{3*5}{4} = \frac{15}{4} = 3.75 dm$ ⇒ LA = SH = 3.75 dm 
Perimetrul = 2*4.8 + 2*3.75 = 9.6 + 7.5 = 17.1 dm
Sper ca te-am ajutat! ^^