Question

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Answer 1

$\sqrt[3]{9}-\dfrac{3}{\sqrt[3]{3}} = \sqrt[3]9 - \dfrac{\sqrt[3]{3^3}}{\sqrt[3]{3}} =\sqrt[3]9 - \sqrt[3]{\dfrac{3^3}{3}} = \sqrt[3]{9}-\sqrt[3]{3^2} = \\ \\ = \sqrt[3]9 - \sqrt[3]9 = 0$