Question

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Answer 1

Răspuns:

m=-2 și n=0.

Explicație pas cu pas:

$- \frac{b}{2a} = 1 = > - b = 2a = > - m = 2 = > m = - 2 \\ - \frac{d}{4a} = - 1 = > b ^{2} - 4ac = 4a = > {m}^{2} - 4n = 4 = > 4 - 4n = 4 = > n = 0$

Answer 2

$\it Pentru\ f(x) =ax^2+bx+c,\ v\hat arful\ parabolei\ este\ V\Big(-\dfrac{b}{2a},\ -\dfrac{\Delta}{4a}\Big).\\ \\ \hat I n\ cazul\ nostru,\ a=1,\ b=m,\ c=n.\\ \\ -\dfrac{b}{2a}=-\dfrac{m}{2}=1 \Rightarrow m=-2\ \ \ \ (*)\\ \\ -\dfrac{\Delta}{4a}=-1 \Rightarrow -\dfrac{m^2-4n}{4}=-1 \Rightarrow m^2-4n=4 \Rightarrow 4n=m^2-4 \stackrel{(*)}{\Longrightarrow}\\ \\ \\ \Rightarrow 4n=4-4=0 \Rightarrow n=0$