Question

........,...............​

Answer 1

Răspuns:

a)logₐ12=logₐ3*4=logₐ3+logₐ4=

logₐ3+logₐ2²=2logₐ2+logₐ3=2m+n

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logₐ∛18=1/3logₐ18=1/3logₐ2*9=

1/3logₐ2+1/3logₐ9=1/3logₐ2+1/3 logₐ3²=1/3m+2/3logₐ3=

m/3+2n/3

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logₐ²Radical de ordinul 4 din 54=logₐradical de ordinul 8 din 54=

1/8logₐ54=1/8logₐ2*27=

1/8(logₐ2+logₐ27)=

1/8 (m+logₐ3³)=

1/8(m+3logₐ3)=1/8(m+3n)

b)a^m+n=a^m*a*a^n

a^m=a^logₐ²=2

a*n=a^logₐ3= 3

a^m*a^n=2*3=6

a^5m+2n=a^5m*a^2n

a^5m=a^5logₐ2=

a^logₐ2⁵=2⁵=32

a^2n=a^2logₐ3=a^logₐ3²=3²=9

a^5m+2n=32*9=288

Pe ultimul nu-l stiu

Explicație pas cu pas: