Question

0,1×{3+3,2×[100×0,01+5,2×(4-1,2×0,1)]}.

Answer 1

0,1x{3+3,2x[100x0,01+5,2x(4-1,2x0,1)]}=
0,1x{3+3,2x[1+5,2x(4-0,12)]}=
0,1x[3+3,2x(1+5,2x3,88)]=
0,1x[3+3,2x(1+20,176)]=
0,1x(3+3,2x21,176)=
0,1x(3+67,76)=
0,1x70,76=
7,076

Answer 2

0.1x{3+3.2x[100x0.01+5.2x(4-1.2x0.1)]}=
0.1x{3+3.2x[100x.0.01+5.2x(4-0.12)=
0.1x[3+3.2x(100x0.01+5.2x3.88)=
0.1x[3+3.2x(1+20.176)=
0.1x(3+3.2x21.176)=
0.1x(3+67.7632)=
0.1x70.7632=7.07632