Question

0,2 : [0,4(6) + 9\20 - 1,1(6)]+ 0,8=

Answer 1

$\frac{2}{10}/ (\frac{42}{90}+ \frac{9}{20}-1 \frac{15}{90})+\frac{8}{10}=\frac{2}{10}/( -\frac{210}{180}+ \frac{84}{180}+ \frac{81}{180})+\frac{8}{10}=\frac{2}{10}/ \frac{45}{180}+\frac{8}{10}.$
Tu in paranteza amplifici prin 2 si 9 ca la numitor sa fie 180
$- \frac{2}{10}* \frac{180}{45}= \frac{36}{45}= \frac{4}{5}$
Amplifici 5 cu doi ca la numitor sa fie 10
$\frac{8}{10}+ \frac{8}{10}= \frac{16}{10}= \frac{8}{5} =1 \frac{3}{5}$