Question

-0,7*1,(6)=
3,17:(-0,317)=
4/5*(4/5) la puterea a 2
(2,5) la puterea a 6 : (2,5) la puterea a 4
(-1,2) la put. a 7 : (-1,2) la put a 6
(3/4) la puterea -2
(2/3)*(2/3) la put. a 2 * (2/3) la put. a 3 : (-2/3) la put. a 6

Va multumesc enorm daca imi acordati ajutor :)

Answer 1

 $0,7= \frac{7}{10};1,(6)=1 \frac{6}{9}= \frac{15}{9}$
$- \frac{7}{10} * \frac{15}{9} =- \frac{7}{6}$
$3 \frac{17}{10} - \frac{317}{1000} = \\ \\ \frac{47}{10} - \frac{317}{100} = \frac{470-317}{1000}= \frac{153}{1000} \\ \\ \frac{4}{5}* (\frac{4}{5})^{2} = \\ \\ \frac{4}{5}* \frac{4^{2}}{5^{2}} = \frac{4^{2}*4}{5^{2}*5} = \frac{64}{125}$
$(\frac{25}{10}) ^{6}: (\frac{25}{10}) ^{4}= (\frac{25}{10}) ^{6}*( \frac{10}{25})^{4} = \frac{25^{2}}{10^{2}} = \frac{625}{100}= \frac{125}{20} = \frac{25}{4}$

$( \frac{3}{4})^{-2} = \frac{9}{16}$

$(- \frac{12}{10})^{7} :(- \frac{12}{10})^{6}=(- \frac{12}{10})^{1}=- \frac{6}{5}$

$[ \frac{2}{3}*( \frac{2}{3})^{2}*( \frac{2}{3})^{3}]:(- \frac{2}{3})^{6} \\ \\ ( \frac{2}{3})^{1+2+3} :(- \frac{2}{3})^{6} \\ \\ ( \frac{2}{3})^{6}:(- \frac{2}{3})^{6}=1$